Linear Acceleration RevisionEquations of Motion 1. v = u + at 2. s = ut + at23. v2 = u2 + 2asv = final velocityu = initial velocitya = accelerations= displacement (not distance)t = timeSolving problems using equations of motion.1. Write down v, u, a, s and t filling in the quantities you know2. Write down the three equations of motion.3. Decide which of the three equations has only one unknown in it.4. Substitute the known values in to this equation and solve to find the unknown.Velocity - Time graphs (for an object travelling with constant acceleration)If a graph is drawn of Velocity (y-axis) against Time (x-axis), the slope of the graph is the acceleration of the object.Note that the area under each section of the graph corresponds to the distance travelled in that section2008 OLFour points a, b, c and d lie on a straight level road.A car, travelling with uniform retardation, passes point a with a speed of 30 m/s and passes point b with a speed of 20 m/s.The distance from a to b is 100 m. The car comes to rest at d.Find (i) the uniform retardation of the car(ii) the time taken to travel from a to b(iii) the distance from b to d(iv) the speed of the car at c, where c is the midpoint of [bd].Solution(i) v2 = u2 + 2as202 = 302 + 2(a)(100)-500 = 200 aa = - 2.5 m s-2(ii) v = u + at20 = 30 - 2.5 tT = 4 s(iii) v2 = u2 + 2as02 = 202 + 2(-2.5)(s)s = 80 m(iv) v2 = u2 + 2as = 202 + 2(-2.5)(40) = 200 v = 10? or 14.1 m s-120 ...
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