Hi Anonymous,How do you solve this integral of 3 sec(2x-1)tan(2x-1)?Mathematically, 3sec(2x-1)tan(2x-1)dx By substitution method,let 2x-1=u, our equation becomes: 3sec(u)tan(u)dx= 2 , by differentiation.du=2dx, dx=2Substituting the value back,3sec() ...
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